Lakshya Education MCQs

Question:

An amount of Rs. 1,00,000 is invested in two types of shares. The first yields an interest of 9% per annum and the second, 11% per annum. If the total interest at the end of one year is 9 3/4 %, then the amount invested in each share was:

Options:
A.Rs 52,500 ; Rs 47,500
B.Rs 72,500 ; Rs 27,500
C.Rs 62,500 ; Rs 37,500
D.Rs 82,500 ; Rs 17,500
E.None of these
Answer: Option C
 -  

 

Let the sum invested at 9% be Rs. a and that invested at 11% be Rs. (100000 - a).

Then,

a x 9 x 1

100

+

(100000 - a) x 11 x 1

100

 

=

100000x

39

x

1

 

4

100

 

 

 

 

 

9a + 1100000 - 11a

=

39000

 = 9750

 

 

100

4

 

 

 

 

 

2a = (1100000 - 975000) = 125000

 

  a = 62500.

 

 

 

 

Sum invested ar 9% = Rs. 62500.

 

 

 

 

Sum invested ar 11% = Rs. (100000 - 62500) = Rs. 37500.

 

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More Questions on This Topic :

Question 1.

A sum of money doubles in 8 years. In how many years, it will treble at S.I?

Options:
  1.    4
  2.    8
  3.    12
  4.    16
  5.    None of these
Answer: Option D
 -  

 

Here P is the same

A simple ratio will give the Time

8

 =

1

 

 

T

2

 

 

 

T = 16 years

 

i.e., In 16 years, the amount will treble

 

Question 2.

Divide Rs. 2379 into 3 parts so that their amount after 2,3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is:

Options:
  1.    759
  2.    818
  3.    792
  4.    828
  5.    None of these
Answer: Option D
 -  

 

  Let the parts be a, b and [2379 - (a + b)].

 

a +

(

a x 2 x

5

)

 = b +

(

b x 3 x

5

)

 = c +

(

c x 4 x

5

)

 

 

 

100

100

100

 

 

 

 

 

11a

=

23b

=

6c

 = K

=>

 a =

10K

, b =

20K

, c =

5K

 

 

 

10

20

5

11

23

6

 

 

 

  But a + b + c = 2379

10K

+

20K

=

5k

 = 2379

 

1380K + 1320K + 1265K = 2379 x 11 x 23 x 6

 

 

 

11

23

6

 

 

 

 

 

 K =

2379 x 11 x 23 x 6

=

3 x 11 x 23 x 6

 

3965

5

 

 

 

 a =

 

10

x

3 x 11 x 23 x 6

 

 = 828.

 

 

11

5

 

 

 Hence, the first part is Rs. 828.

 

Question 3.

Saranya gives 50 times the rent per annum to purchase a plot from L.I.C. Find the rate of interest from the amount paid by him?

Options:
  1.    1%
  2.    2%
  3.    3%
  4.    15%
  5.    None of these
Answer: Option B
 -  

 

Let the annual rent be Rs. X.

 

I = X; P = 50X, n = 1

 

The rate of interest =

100I

=

100X

 % = 2%

Pn

50X

 

Question 4.

How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% pa simple interest?

Options:
  1.    21
  2.    28
  3.    56
  4.    76
  5.    None of these
Answer: Option C
 -  

Simple interest is given by the formula SI = (P x T x R)/100,

where P is the principal,T is the number of years for which it is invested,
 

R is the rate of interest per annum. In this case,
 

Rs. 1250 has become Rs.10,000.
 

Therefore, the interest earned = 10,000 – 1250 = 8750.
 

8750 = [(1250 x T x 12.5)/100]
 

 T = 700 / 12.5 = 56 years

Question 5.

A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks?

Options:
  1.    100
  2.    80
  3.    70
  4.    60
  5.    None of these
Answer: Option A
 -  

Let the maximum marks be x.
 

From the given statement pass percentage is 42% - 12% = 30%
 

By hypothesis, 30% of x – 20% of x = 10 (marks)
 

i.e., 10% of x = 10
 

Therefore, x = 100 marks.

Question 6.

A sum of Rs. 800 amounts to Rs. 920 in 3 years at simple interest. If the interest rate is increased by 3%, it would amount to how much?

Options:
  1.    764
  2.    992
  3.    850
  4.    770
  5.    None of these
Answer: Option B
 -  

S.I = Rs. (920 – 800) = Rs. 120; P = Rs. 800, T = 3 yrs

 R = ( 100 X 120 )% =  5%
              800 X 3

New rate = (5 + 3) % = 8%

New S.I. = Rs. (800 X 8 X 3) == Rs. 192.
                              100

New amount = Rs. (800 + 192) = Rs. 992