## Lakshya Education MCQs

Question:

An amount of Rs. 1,00,000 is invested in two types of shares. The first yields an interest of 9% per annum and the second, 11% per annum. If the total interest at the end of one year is 9 3/4 %, then the amount invested in each share was:

Options:
 A. Rs 52,500 ; Rs 47,500 B. Rs 72,500 ; Rs 27,500 C. Rs 62,500 ; Rs 37,500 D. Rs 82,500 ; Rs 17,500 E. None of these
-

Let the sum invested at 9% be Rs. a and that invested at 11% be Rs. (100000 - a).

Then,

a x 9 x 1

100

+

(100000 - a) x 11 x 1

100

=

100000x

39

x

1

4

100

9a + 1100000 - 11a

=

39000

= 9750

100

4

2a = (1100000 - 975000) = 125000

a = 62500.

Sum invested ar 9% = Rs. 62500.

Sum invested ar 11% = Rs. (100000 - 62500) = Rs. 37500.

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## More Questions on This Topic :

Question 1.

A sum of money doubles in 8 years. In how many years, it will treble at S.I?

Options:
1.    4
2.    8
3.    12
4.    16
5.    None of these
-

Here P is the same

A simple ratio will give the Time

8

=

1

T

2

T = 16 years

i.e., In 16 years, the amount will treble

Question 2.

Divide Rs. 2379 into 3 parts so that their amount after 2,3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is:

Options:
1.    759
2.    818
3.    792
4.    828
5.    None of these
-

Let the parts be a, b and [2379 - (a + b)].

a +

(

a x 2 x

5

)

= b +

(

b x 3 x

5

)

= c +

(

c x 4 x

5

)

100

100

100

11a

=

23b

=

6c

= K

=>

a =

10K

, b =

20K

, c =

5K

10

20

5

11

23

6

But a + b + c = 2379

10K

+

20K

=

5k

= 2379

1380K + 1320K + 1265K = 2379 x 11 x 23 x 6

11

23

6

K =

2379 x 11 x 23 x 6

=

3 x 11 x 23 x 6

3965

5

a =

10

x

3 x 11 x 23 x 6

= 828.

11

5

Hence, the first part is Rs. 828.

Question 3.

Saranya gives 50 times the rent per annum to purchase a plot from L.I.C. Find the rate of interest from the amount paid by him?

Options:
1.    1%
2.    2%
3.    3%
4.    15%
5.    None of these
-

Let the annual rent be Rs. X.

I = X; P = 50X, n = 1

The rate of interest =

100I

=

100X

% = 2%

Pn

50X

Question 4.

How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% pa simple interest?

Options:
1.    21
2.    28
3.    56
4.    76
5.    None of these
-

Simple interest is given by the formula SI = (P x T x R)/100,

where P is the principal,T is the number of years for which it is invested,

R is the rate of interest per annum. In this case,

Rs. 1250 has become Rs.10,000.

Therefore, the interest earned = 10,000 – 1250 = 8750.

8750 = [(1250 x T x 12.5)/100]

T = 700 / 12.5 = 56 years

Question 5.

A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks?

Options:
1.    100
2.    80
3.    70
4.    60
5.    None of these
-

Let the maximum marks be x.

From the given statement pass percentage is 42% - 12% = 30%

By hypothesis, 30% of x – 20% of x = 10 (marks)

i.e., 10% of x = 10

Therefore, x = 100 marks.

Question 6.

A sum of Rs. 800 amounts to Rs. 920 in 3 years at simple interest. If the interest rate is increased by 3%, it would amount to how much?

Options:
1.    764
2.    992
3.    850
4.    770
5.    None of these