• The given box contains a total of 160 Rupees and the ratio of one rupee, 50 paisa and 25 paisa coins is 4:5:6.
• Let us assume ‘x’ number of one rupee coins, ‘y’ number of 50 paisa coins and ‘z’ number of 25 paisa coins, then the equation can be written as:
• 1x + 0.50y + 0.25z = 160
• We can rewrite the equation as 4x + 5y + 6z = 800
• Now, we can solve the equation using the expressions of x, y, and z
• x + 2y + 4z = 400
• On solving, we get
x = 400 – 2y – 4z
• Substituting the value of x in 4x + 5y + 6z = 800
• 400 + 5y + 6z = 800
• 5y + 6z = 400
• On solving, we get
y + 2z = 80
• Substituting the value of y in x + 2y + 4z = 400
• 400 – 2(80-2z) – 4z = 400
• 8z = 320
• On solving, we get
z = 40
• Therefore, the required number of 25 paisa coins is 40.
Hence, the correct answer is Option C.

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