Question
Which of the following trigonometric expressions is equal to sec6 θ ?
Answer: Option A
:
A
sec6θ=(sec2θ)3
=(tan2θ+1)3……(1+tan2θ=sec2θ)
=tan6θ+3tan4θ+3tan2θ+1
=tan6θ+3tan2θ(tan2θ)+3tan2θ+1
=tan6θ+3tan2θ(sec2θ−1)+3tan2θ+1
=tan6θ+3tan2θsec2θ−3tan2θ+3tan2θ+1
=tan6θ+3tan2θsec2θ+1
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:
A
sec6θ=(sec2θ)3
=(tan2θ+1)3……(1+tan2θ=sec2θ)
=tan6θ+3tan4θ+3tan2θ+1
=tan6θ+3tan2θ(tan2θ)+3tan2θ+1
=tan6θ+3tan2θ(sec2θ−1)+3tan2θ+1
=tan6θ+3tan2θsec2θ−3tan2θ+3tan2θ+1
=tan6θ+3tan2θsec2θ+1
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