The mean of the following distribution is x i 10 13 16 19 f i 2 5 7 6 Options: A . &nbsp15.55 B . &nbsp15.35 C . &nbsp14.3 D . &nbsp16

Answer: Option A : A Mean of ungrouped frequency distribution is given by ¯ x = ∑ n i = 1 f i x i ∑ n i = 1 f i = ( 10 × 2 + 13 × 5 + 16 × 7 + 19 × 6 ) ( 2 + 5 + 7 + 6 ) = 311 20 Therefore, themean of the data is 15.55.

The mean of the following distribution is xi10131619fi2576

Question

The mean of the following distribution is

\begin{matrix} x_{i} & 10 & 13 & 16 & 19 f_{i} & 2 & 5 & 7 & 6 \end{matrix}

Options:

A . 15.55

B . 15.35

C . 14.3

D . 16

Answer: Option A
:
A
Mean of ungrouped frequency distribution is given by

¯ x = \frac{\sum_{i = 1}^{n} f_{i} x_{i}}{\sum_{i = 1}^{n} f_{i}}

= \frac{(10 \times 2 + 13 \times 5 + 16 \times 7 + 19 \times 6)}{(2 + 5 + 7 + 6)}

= \frac{311}{20}

Therefore, themean of the data is 15.55.

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