sin18∘cos72∘=

Question

\frac{s i n 18^{\circ}}{c o s 72^{\circ}} =

Answer:
:

\frac{sin 18^{\circ}}{cos 72^{\circ}}

= \frac{sin (90^{\circ} - 72^{\circ})}{cos 72^{\circ}}

= \frac{cos 72^{\circ}}{cos 72^{\circ}} = 1

s i n (90^{\circ} - A) = c o s A

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