Lakshya Education MCQs

Question: If sinx2=sin β

where π2βπ2 then, 
A.x=nπ+(−1)n β
B.x=2nπ+(−1)n β
C.x=nπ+(−1)n 2β
D.x=2nπ+(−1)n 2β
Answer: Option D
: D


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More Questions on This Topic :

Question 1. Find the general solution of sin x+2=sin x
  1.    x=nπ+(−1)n+1π4
  2.    x=nπ+(−1)nπ4
  3.    x=nπ+(−1)nπ3
  4.    x=nπ+(−1)n3π4
Answer: Option A
: A

Question 2. What is the principal solution of 4 cos2x8 cos x+3=0 ?
  1.    x=π6
  2.    x=π4
  3.    x=π3
  4.    x=π2
Answer: Option C
: C

Question 3. Find the principal solution of 3cos2θcos 2θ=1
  1.    θ=0
  2.    θ=−π2
  3.    θ=π2
  4.    θ=π
Answer: Option C
: C

Question 4. The general solution of tan x=tan α, α ϵ (π2,π2) is 
  1.    x=nπ+(−1)nα, n ϵ Z
  2.    x=nπ+α, n ϵ Z
  3.    x=2nπ±α, n ϵ Z
  4.    None of these
Answer: Option B
: B

The general solution oftanx=tanα,αϵ(π2,π2) is

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