Lakshya Education MCQs

Question: I take a 3 digit number with distinct digits. I can get 6 different 3 digit numbers by rearranging the digits of this number.
Options:
A.True
B.False
C.50
D.51
Answer: Option A
: A

Let the3 digit number beabc.On rearrangingthedigits I get, abc, bac, cba, cab, acb, bca. Hence Iwill get 6 three digit numbers.

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More Questions on This Topic :

Question 1. What is the remainder when 1591 is divided by 1000?
  1.    91
  2.    0
  3.    591
  4.    1
Answer: Option C
: C

On dividing 1591 by 1000, the remainder is the last 3 digits. Hence it is 591.
Question 2. (f × 100) + (d × 10) + e is written as
  1.    def
  2.    efd
  3.    fde
  4.    edf
Answer: Option C
: C

(f×100) + (d×10) + e is written asfde which is a three digit number.

For example, (2 × 100) + (3 × 10) + 1 is the expanded form of 231.
Question 3. Find A in the addition, given that B is a natural number.

 

 A+A+AB A
  1.    1
  2.    5
  3.    3
  4.    2
Answer: Option B
: B

The sum of three A's is such anumber that hasA in its ones place. Therefore, the sum of two A's must be a number whose ones digit is 0. This happens only for A = 0 and A = 5 If A = 0, then the sum is 0 + 0 + 0 = 0, which makes B = 0.

Given that B is a natural number, thereforeB cannot be equal to 0. So we don't considerthis possibility.

Hence, A = 55+5+515 Therefore, A= 5 and B= 1
Question 4. How many numbers are divisible by 2 from 1 to 100?
  1.    23
  2.    49
  3.    50
  4.    51
Answer: Option C
: C

From 1 to 4 there are 2 numbers divisible by 2, which are 2 and 4. From 1 to 10, there are 5 numbers, which are 2, 4, 6, 8, 10. Hence, the number of numbers divisible by 2 is half the number up to which we count. Half of 100 is 50. Hence 50 is the number of numbers divisible by 2 from 1 to 100.

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