Lakshya Education MCQs

Question: I take a 3 digit number with distinct digits. I can get 6 different 3 digit numbers by rearranging the digits of this number.
Options:
 A. True B. False C. 50 D. 51
: A

Let the3 digit number beabc.On rearrangingthedigits I get, abc, bac, cba, cab, acb, bca. Hence Iwill get 6 three digit numbers.

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More Questions on This Topic :

Question 1. What is the remainder when 1591 is divided by 1000?
1.    91
2.    0
3.    591
4.    1
: C

On dividing 1591 by 1000, the remainder is the last 3 digits. Hence it is 591.
Question 2. (f × 100) + (d × 10) + e is written as
1.    def
2.    efd
3.    fde
4.    edf
: C

(f×100) + (d×10) + e is written asfde which is a three digit number.

For example, (2 × 100) + (3 × 10) + 1 is the expanded form of 231.
Question 3. Find A in the addition, given that B is a natural number.

A+A+AB A
1.    1
2.    5
3.    3
4.    2
: B

The sum of three A's is such anumber that hasA in its ones place. Therefore, the sum of two A's must be a number whose ones digit is 0. This happens only for A = 0 and A = 5 If A = 0, then the sum is 0 + 0 + 0 = 0, which makes B = 0.

Given that B is a natural number, thereforeB cannot be equal to 0. So we don't considerthis possibility.

Hence, A = 55+5+515 Therefore, A= 5 and B= 1
Question 4. How many numbers are divisible by 2 from 1 to 100?
1.    23
2.    49
3.    50
4.    51