Question
Find A in the addition, given that B is a natural number.
A+A+AB A
A+A+AB A
Answer: Option B
:
B
The sum of three A's is such anumber that hasA in its ones place.
Therefore, the sum of two A's must be a number whose ones digit is 0.
This happens only for A = 0 and A = 5
If A = 0, then the sum is 0 + 0 + 0 = 0, which makes B = 0.
Given that B is a natural number, thereforeB cannot be equal to 0. So we don't considerthis possibility.
Hence, A = 55+5+515
Therefore, A= 5 and B= 1
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:
B
The sum of three A's is such anumber that hasA in its ones place.
Therefore, the sum of two A's must be a number whose ones digit is 0.
This happens only for A = 0 and A = 5
If A = 0, then the sum is 0 + 0 + 0 = 0, which makes B = 0.
Given that B is a natural number, thereforeB cannot be equal to 0. So we don't considerthis possibility.
Hence, A = 55+5+515
Therefore, A= 5 and B= 1
Was this answer helpful ?
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